Question

Math 2 Of high school

Answer 1

• B. BC = 18 so ∆ABC ～ ∆DEF by SAS

Explanation:

`\bf \cfrac{AB}{DE} = \cfrac{BC}{EF}`

• 
  `\bf \cfrac{15}{10} = \cfrac{BC}{12}`
• 
  `\bf \cfrac{3}{2} = \cfrac{BC}{12}`
• 
  `\bf BC = \cfrac{3}{2} * 12`
• 
  `\bf 3 * 6`
• 
  `\bf BC = 18`
• 
  `\bf \angle B = \angle \: E`

So, ∆ABC ～ ∆DEF by SAS.

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