Question

If excess sodium is added to 0.10 L of 1.00 M hydrochloric acid solution, how many moles of NaCl is formed?

Na (s) + HCI (aq)
1.00
0.10
0.50
0.05

Answer 1

=> 0.10 moles

Step-by-step explanation:

The question is asking us to find the moles of NaCl cid formed.

We have been provided with;

0.10 L of 1.0 M NaOH.

We know that mole ratio of the reaction is 1:1 and also the molarity of a solution is contained in 1 L or 1000 mL or 1000 cm³.

This means that;

1.0 M is contained in 1.0 L.

X mol is contained in 0.10 L

`x \: mol \: = (0.1 * 1.0)/(1.0) \\ = 0.10 \: mol`

= 0.10 moles of NaCl formed