Question

A gas sample has a volume of 178 ml of 0.00 degrees

c. the temperature is raised (at constant pressure) until the volume reaches 211 ml. what is the temperature of the gas sample in degrees c at this volume?

Answer 1

Answer: The temperature of the gas was 50.46°C.

Step-by-step explanation:

To calculate the final volume when temperature increases, we use Charles' Law which states that the volume is directly proportional to the temperature of the gas if number of moles and pressure remains constant.

Mathematically,

`V\propto T\\\\(V_1)/(T_1)=(V_2)/(T_2)`

where,

`V_1\text{ and }T_1` = Initial volume and temperature

`V_2\text{ and }T_2` = Final volume and temperature

We are given:

`V_1=178mL\\T_1=0^oC=273K\\V_2=211mL\\T_2=?`

Putting values in above equation, we get:

`(178)/(273)=(211)/(T_2)`

`T_2=323.61K=50.46^oC` (Conversion factor: T(K) = T(°C) + 273.15)

Hence, the temperature of the gas is 50.46°C