Question

Please help on this one? :)

Answer 1

`x = \frac32y + 9`

Explanation:

You want to transform this function into an x = ... form:

`y = \frac23x - 6`

add 6 to both sides and swap

`\frac23x = y+6`

multiply by 3/2

`x = \frac32(y+6) = \frac32y + 9`