Final answer:
Part 3) Option C infinitely solutions
Part 4) Option D none
Part 5) Option C infinitely solutions
Part 6) Option D none
Step-by-step explanation:
To determine the number of solutions for a system of equations, we need to solve the equations simultaneously and see how many common solutions they have.
Let's go through each system of equations:
System 1:
4x = -12y + 16 and x + 3y = 4
By rearranging the second equation, we can rewrite it as x = 4 - 3y.
Substituting x in the first equation, we get 4(4 - 3y) = -12y + 16.
Simplifying, we have 16 - 12y = -12y + 16.
This equation simplifies to 0 = 0, which means the two equations are equivalent and represent the same line. Therefore, the system has infinitely many solutions (c).
System 2:
y = 6x + 2 and y = 6x + 4
Since both equations have the same slope, but different y-intercepts, the lines represented by the equations are parallel. Parallel lines never intersect, so the system has no solution (d).
System 3:
x - 2y = 6 and 3x - 6y = 18
Dividing the second equation by 3, we get x - 2y = 6.
This shows that the two equations represent the same line. Therefore, the system has infinitely many solutions (c).
System 4:
y - 7x = -14 and 7y - 49x = -2
Multiplying the first equation by -7, we get -7y + 49x = 98.
Equation A and equation B are parallel lines, because has the same slope.
The slope is equal to m=7 therefore the system has no solution.