Question

In a race, Bethany is located ​ −60 1/2 ​ meters relative to her friend, Monica, after 2 1/5 minutes. Assuming both girls are running at a constant rate, what was Bethany's location relative to Monica's after 1 minute? Enter your answer as a mixed number, in simplest form, in the box.

Answer 1

Answer: Bethany's location relative to Monica's after 1 minute is
`27(1)/(2)\ meters`

Explanation:

Since we have given that

After
`2(1)/(5)\ minutes=(11)/(5)\ minutes`,

Distance between Bethany is located relative to her friend is given by

`60(1)/(2)\ meters\\\\=(121)/(2)\ meters`

We need to find the distance between Bethany's location relative to Monica's after 1 minute.

We will use "Unitary Method":

After
`(11)/(5)\ minutes`,

`Distance=(121)/(2)\ meters`

After 1 minute,

`Distance=((121)/(2))/((11)/(5))\\\\Distance=(121* 5)/(11* 2)\\\\Distance=(55)/(2)\ meters\\\\Distance=27(1)/(2)\ meters`

Hence, Bethany's location relative to Monica's after 1 minute is
`27(1)/(2)\ meters`