Question

-3g^-2hk^-2/-6h^0 Simplify

Answer 1

`a^0=1\ \text{for any real number except 0}\\\\\text{Therefore if}\ h\\eq0,\ h^0=1.\\\\(-3g^(-2)hk^(-2))/(-6h^0)=(-3)/(-6)g^(-2)hk^(-2)=(1)/(2)\cdot(1)/(g^2)\cdot h\cdot(1)/(k^2)=\boxed{(h)/(2g^2k^2)}\\\\Used\ a^(-n)=(1)/(a^n)`