Question

Consider the chemical equations shown here.

2NO2(g) ----> 2NO(g) + O2(g)

2NO(g) -----> N2(g) + O2(g)

N2(g) + 2O(g) ----> N2O4(G)


What is the equation for the overall reaction obtained by adding these equations?


2NO2(G) ----> N2O4(g)


2N204(g) + 2NO(g) ----> 2NO2(g) + 02(g)


N2 + O2(g) + 2NO(g) ----> N2O4 (g)

The answer is A

Answer 1

A.)

Step-by-step explanation:

Answer 2

Answer: Chemical equation for the overall reaction obtained by adding these three given equations is:

`2NO_2(g)\rightarrow N_2O_4(g)`

Step-by-step explanation:

`2NO_2(g)\rightarrow2NO(g)+O_2(g)`...(1)

`2NO(g)\rightarrow N_2(g)+O_2(g)`...(2)

`N_2(g)+2O_2(g)\rightarrow N_2O_4(g)`...(3)

If the same compounds is on same sides in the reactions then add them.

If the same compound is on different sides of the reaction then subtract.

Adding (1) and (2)

`2NO_2(g)+2NO(g)\rightarrow 2NO(g)+O_2(g)+N_2(g)+O_2(g)`

NO is present on both sides, which means it will get cancel out.
`O_2` is on same side it will get added up.

`2NO_2(g)\rightarrow N_2(g)+2O_2(g)`..(4)

Similarly, on adding (3) in (4) we get:

`2NO_2(g)\rightarrow N_2O_4(g)`

Above equation is obtained by adding given three equations.