According to the fundamental theorem of algebra how many zeros does the function f(x)=15x^23+41x^19+13x^5-10

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asked Sep 17, 2020 34.3k views

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DroidT · Answer 1 · 2020-09-20T16:20:30+0000

According to the fundamental theorem of algebra, that function has 23 zeros.
Whatever degree the polynomial is, that is how many zeros it will have.
Hope I helped!

According to the fundamental theorem of algebra how many zeros does the function f(x)=15x^23+41x^19+13x^5-10

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