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What is the value of 6x^2+4x+8, when x =7

What is the value of 6x^2+4x+8, when x =7
asked 79.4k views
4 votes
What is the value of 6x^2+4x+8, when x =7

asked
User Ronald Oussoren
by
7.9k points

1 Answer

5 votes

Answer:220

Explanation:

42x42=1764

1764x+4x+8

1764-4=1760 and 4x cancels out

so what should be left over is

1760+8 then you divide both of the numbers and get 1760/8= 220

answered
User VeeeneX
by
8.2k points
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