Question

What is the temperature of 0.750 mol of a gas stored in a 6,850 mL cylinder at 2.21 atm? Use PV=nRT and R=0.0821 (L•atm)/(mol•K)

A.)2.95 K
B.)5.24 K
C.)138 K
D.)246 K

Answer 1

D. 246k

Step-by-step explanation:

Edg

Answer 2

Using the formula PV=nRT
we know:
n= 0.750mol
R= 0.0821 (L•atm)/(mol•K)
V= 6850 ml = 6.85 L
P= 2.21 atm
and we need to find T
all you have to do is divide PV by nR and you will find T, like this:

`t = (p * v)/(n * r) \\ t = (2.21atm * 6.85l)/(0.750mol * 0.0821 (atm * l)/(mol * k) ) \\ t = 246k`
The temperature of the gas is D)246 K