Question

I need help with this:

A big ship drops its anchor.


The variable ll models the anchor's elevation (in meters) relative to the water's surface tt seconds after the ship drops its anchor.


l=-2.4t+75l=−2.4t+75


What is the initial height of the anchor?

Answer 1

The answer is 75 meters.

Explanation:

I= -2.4t + 75

I= -2.4(0) + 75

I= 0 + 75

I= 75 meters

I did it on Khan and it was correct.

Answer 2

Answer: 75 meters

Explanation:

Given: The variable ll models the anchor's elevation (in meters) relative to the water's surface t seconds after the ship drops its anchor as

`I=-2.4t+75`

To find the initial height, substitute t=0 in the equation, we get

`\Rightarrow\ I=-2.4(0)+75`

`\Rightarrow\ I=75`

Therefore, the initial height of the anchor = 75 meters .