asked 167k views
3 votes
What is tje equation for the linear function whose graph contains the points (2,5) and (3,0) ?

1 Answer

4 votes
In order to find a slope, there is an equation:

Y2-Y1/X2-X1

X1=2
X2=3
Y1=5
Y2=0

0-5= -5
3-2=1

Since slope is written as Y/X, slope would be-5/1 or simply, -5.

Now, we need to find the y-intercept.

To do this, shift the original equation:

Original equation: y=-5x+b

Shifted equation: b=y+5x

Now, plug in one of the points.

Let's use (2,5)

b=5+5(2)

5*2=10
10+5=15

y-intercept=15

So, the full equation of the line would be:

y=-5x+15
answered
User Oleg Alexander
by
8.6k points

Related questions

1 answer
2 votes
12.8k views
asked May 20, 2024 79.3k views
Monique asked May 20, 2024
by Monique
7.9k points
1 answer
1 vote
79.3k views
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.