Question

The average speed of oxygen molecules in air is about ____. (1 point) 0 km/h 170 km/h 1700 km/h 17,000 km/h

Answer 1

The answer to your question is 1700 km/h

I hope this helps

Answer 2

The average speed is calculated using the following formula
`speed = \sqrt{(3kT)/(m) }`

Where

`k = 1.381 X  10^(-23) J / K`

T = 298 K [room temperature]

m = mass of each molecule of oxygen

mass of one mole of oxygen molecules = 32 g / mol

mass of one molecule of oxygen will be =
`(32)/(6.023 X 10^(23) )`

mass of one molecule of oxygen will be =
`5.31 X 10^(-23) g = 5.31 X 10^(-26) kg`

putting values

average speed =
`\sqrt{(3 X 1.381 X  10^(-23) X 298)/(5.31 X 10^(-26) kg) }`

Average speed = 482.19 m / s

average speed = 1735.8 km / h

so approx = 1700 km/h