Question

What is the value of k in the function ƒ(x) = 112 - kx if ƒ(-3) = 121?

Answer 1

hello :

put - 3 in f(x) you have : 112 - k(-3) = 121

solve 112 +3k =121

3k = 121 -112

3k = 9

k = 3

Explanation:

Answer 2

k =3

Explanation:

f(x) = 112 -kx

Let x = -3

f(-3) =112 -k(-3)

We know that it equals 121

121 = 112 +3k

Subtract 112 from each side

121-112 =112 -112 +3k

9 = 3k

Divide each side by 3

9/3 = 3k/3

3 =k