Happy New Year from MrBillDoesMath! 
 
Answer: 
 i ^ (2n) = (i^2)^n = (-1)^n = -1 if n is odd and = 1 if n is even
 i ^ (2n+1) = i^(2n)* i = -1 * i = -i if n is odd and = 1*i = i if n is even
Not sure if this answers your question but hopefully pushes you n the right direction.
 
Thank you, 
 
MrB