Question

If 0.523 mol of argon occupies a volume of 723 mL at a particular temperature and pressure, what volume would 0.735 mol of argon occupy under the same conditions?

Answer 1

The gas 0.735/0.523=1.405moles.

so 1.405 times of gas is present than what was at the start. 0.523moles of argon took up 0.723L(723mL) so 1.405 times as much gas would take 1.405 times as much space. so the volume would be ,

1.405*0.723=1.015L