Question

Jared has a bag that contains 8 blue marbles, 6 red marbles, and 10 green marbles. He selects a marble, replaces it in the bag, and then selects another marble. What is the probability that both marbles are green? Fraction form

Answer 1

\frac{25}{144}[/tex]

All the probabilities will be written as fractions, and all the denominators will be the same, because all the marbles are together. The denominator will be equal to the sum of all marbles in the bag:

6 + 8 + 10 = 24

`(8)/(24)` = probability of getting a blue marble

`(6)/(24)` = probability of getting a red marble

`(10)/(24)` = probability of getting a green marble

Now, the final probability. The probability of both marbles selected being green, will be represented by a multiplication,

`(10)/(24) * (10)/(24) = (100)/(576) = (25)/(144)`

Hope it helped,

BioTeacher101

Answer 2

Total marbles = 8 + 6 +10 = 24

The probability of picking a green would be 10/24, which reduces to 5/12.

Since they put the first marble back, the probability of picking another green one would be the same as the first time, 5/12.

The probability of picking green twice would be 5/12 x 5/12 = 25/144