An incompressible fluid flows steadily through a pipe that has a change in diameter. The fluid speed at a location where the pipe diameter is 8.8 cm is 2.4 m/s. Calculate the fl…

Question

asked Apr 10, 2021 209k views

1 Answer

Hamid Bayat · Answer 1 · 2021-04-14T11:14:58+0000

Answer:

The value is
$v_2 = 5.53 \ m /s$

Step-by-step explanation:

From the question we are told

The pipe diameter at location 1 is
$d = 8.8 \ cm = (8.8 )/(10) = 0.88 \ m$

The velocity at location 1 is
$v_1 = 2.4 \ m /s$

The diameter at location 2 is
$d_2 = 5.80 \ cm = 0.58 \ m$

Generally the area at location 1 is

$A_1 = \pi * (d^2)/( 2)$

=>
$A_1 = \pi * (0.88^2)/( 2)$

=>
A_1 = 3.142 * (0.88^2)/( 2)

=>
$A_1 = 1.2166 \ m^2$

Generally the area at location 1 is

$A_2 = \pi * (d_1^2)/( 2)$

=>
$A_2 = \pi * (0.58^2)/( 2)$

=>
$A_2 = 0.528 \ m^2$

Generally from continuity equation we have that

A_1 * v_1 = A_2 * v_2

=>
1.2166 * 2.4 = 0.528 * v_2

=>
$v_2 = 5.53 \ m /s$