Question

Find the equation of the line which:

passes through (3, 4) and is perpendicular to y=x+2

Answer 1

y = -x + 7.

Explanation:

General form:-

y = mx + c where m = slope. So:

y = x + 2 has a slope of 1.

The line perpendicular to it has slope -1/1 = -1

To find the required line we use the point-slope form with m = -1, x1 = 3 and y1 = 4.

y - y1 = m(x - x1)

y - 4 = -1(x - 3)

y - 4 = -x + 3

y = -x + 7.

Answer 2

Perpendicular means slope is negative reciprocal, so m=-1

From here, plug in point (3, 4) to find b

The answer is

y=-x+7

Hope this helped :)