Question

Ganymede is a moon of Jupiter (mass = 1.90 x 1027 kg). It orbits Jupiter in a circle of radius 1.07 x 109 m. What is Ganymede's period in hours)?

Answer 1

T = 171.59 hours

Step-by-step explanation:

Mass of Ganymede,
`M=1.9* 10^(27)\ kg`

Radius of the orbit,
`R=1.07* 10^9\ m`

We need to find Ganymede's period. Let time is T. Using Kepler's third law of motion.

`T^2=(4\pi^2)/(GM)r^3\\\\T^2=(4\pi^2)/(6.67* 10^(-11)* 1.9* 10^(27))* (1.07* 10^9)^3\\\\T=617754.35\ s`

or

T = 171.59 hours

Hence, Ganymede's period is 171.59 hours.