Answer:
AgN3
Step-by-step explanation:
Mass of nitrogen N is given as 24.36 g
Molar mass of nitrogen N= 14 g/mol.
amount of substance in mol of N = mass/molar mass
=24.36 g/ 14 g/mol.
=1.74 mol.
Given mass of silver= 62,64 g.
Molar mass of silver Ag=107.87 g/mol
Number of mols=62.64 g ÷ 107.87 g/mol.
=0.58 mol.
Ratio of number of mol of N and number of mols of Ag = 1.74 mol / 0.58 mol
=3:1
Hence, empirical formula is AgN₃.