Answer:
 
 16 The value by which (8x^2 - 9y^2)(8x 
2
 −9y 
2
 ) is larger than (3x^2 - 2y^2)(3x 
2
 −2y 
2
 ) is as follows:-
\begin{gathered}(8x^2 - 9y^2) - (3x^2 - 2y^2)\\= 8x^2 - 9y^2 - 3x^2 + 2y^2\\= 5x^2 -7y^2\end{gathered} 
(8x 
2
 −9y 
2
 )−(3x 
2
 −2y 
2
 )
=8x 
2
 −9y 
2
 −3x 
2
 +2y 
2
 
=5x 
2
 −7y 
2