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(1) 16 liters of kerosene is needed for 12 stoves 14

hours. find the quantity of kerosene needed for seven
stoves for 18 hours by using unitary methods with full explain


asked
User Vikramjb
by
8.4k points

1 Answer

1 vote

9514 1404 393

Answer:

12 liters

Explanation:

The kerosene usage is assumed to be jointly proportional to the number of stoves and the number of hours. That is ...

v = k·s·h . . . . . for s stoves running h hours

Then the value of k is ...

k = v/(sh) = (16 L)/(12·14) = 2/21 . . . . liters per stove-hour

Then the volume of kerosene required for 7 stoves and 18 hours is ...

v = (2/21)·s·h

v = (2/21)(7)(18) = 12 . . . liters

answered
User Robert Campbell
by
8.4k points

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