Question

Samuel and Jill had 576 stamps in all. Samuel gave 1/7 of his stamps

to Jill. Then, Jill gave 1/4 of the total number of stamps she now had to
Samuel. In the end, both of them had the same number of stamps.
What was the difference in the number of stamps they each had at first?

Answer 1

128

Explanation:

Sam has X stamps.

Jill has (576-X) Stamps.

X-x/7 = 6x/7 = Sam's bal.

576-x + x/7 = 576 - 6x/7 = Jill's bal.

1/4(576-6x/7) = 144 - 6x/28

3/4(576-6x/7) = 432 - 9x/14 = Jill's new

bal.

6x/7 + 144-6x/28 = 144 + 24x/28-6x/28 =

144 + 9x/14 = Sam's new bal.

Jill's new bal = Sam's new bal

432 - 9x/14 = 144 + 9x/14

18x/14 = 144-432 = 288

18x = 4032

X = 224

576-X = 576-224 = 352.

Difference = 352 - 224= 128