Question

A chord AB divides a circle of radius 8 cm into two segments. If AB subtends a

central angle of 45, find the area of the minor segment.

Answer 1

Area of the minor segment = 2.505324230749 cm²

Explanation:

Area of the minor segment

= Area of the sector ABC - Area of the triangle ABC

……………………………………………………………………………………

• Area of the sector ABC

= Area of the whole circle ÷ 8

= (π×8²) ÷ 8

= 8π

______

•• Area of the triangle ABC

= (1÷2) × CA × CB × sin(45)

= (1÷2) × 8 × 8 × (√2/2)

= 16√2

______

Thus

Area of the minor segment

= 8π - 16√2

= 2.505324230749