asked 13.9k views
3 votes
Find the 75th term of the following arithmetic sequence.
12, 21, 30, 39,

1 Answer

4 votes

9514 1404 393

Answer:

678

Explanation:

The sequence has a first term of 12 and a common difference of 21-12 = 9. The explicit formula for the n-th term is ...

an = a1 +d(n -1)

For a1 = 12 and d = 9, this is ...

an = 12 + 9(n -1)

Using 75 for the value of n, we have ...

a75 = 12 + 9(75 -1) = 12 + 666 = 678

The 75th term is 678.

answered
User Redzarf
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