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Find three consecutive even integers such that the sum of the second and third is 3 times the first integer.

asked
User Stesch
by
8.4k points

1 Answer

4 votes

Answer:


6,
8 and
10

Explanation:

Let
x = smallest consecutive even integer.

Since the second and third consecutive even integers can be expressed by our smallest even consecutive integer, we can express them as:

Second consecutive even integer =
x+2

Third consecutive even integer =
x+4

From "the sum of the second and third is 3 times the first integer", we can write:


x+2+x+4 = 3x


2x+6 = 3x (collect like-terms)


x=6

∴ The first consecutive even integer is 6

Now, we can use substitution to find the values of the second and third consecutive even integers:

Second consecutive integer =
x+2


=6+2


=8

Third consecutive integer =
x+4


=6+4


=10

∴ The three consecutive even integers are
6,
8 and
10.

Hope this helps :)

answered
User Hussein El Feky
by
8.3k points

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