Question

Can someone answer this for me?

Answer 1

Answer: The moles of nitrogen dioxide produced are 96.3

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
`6.023* 10^(23)` of particles.

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given volume}}{\text {Molar volume}}=(3714L)/(22.4L)=165.8moles`

`4NH_3(g)+7O_2(g)\rightarrow 4NO_2(g)+6H_2O(g)`

According to stoichiometry:

7 moles of oxygen
`(O_2)` produce = 4 moles of nitrogen dioxide
`(NO_2)`

Thus 168.5 moles of oxygen
`(O_2)` will produce =
`(4)/(7)* 168.5=96.3` moles of nitrogen dioxide
`(NO_2)`