Question

4.

Given sin 0 = { and angle 0 is in Quadrant II, what is the exact value of cos 0 in
simplest form? Simplify all radicals if needed.

Answer 1

Sin0= y/r

X= -4 and r= 9 (radius is also the hypotenuse)

In quadrant II y is positive

X^2 +y^2 = r^2

-4^2 + y^2 = 9^2

16 + y^2 = 81

Y^2 = 81-16

Y^2 = 65

Y= sqrt65

Sin0= sqrt65/9

Explanation: