Question

(2+3i)(1-2i)

What is the product of the complex number

Answer 1

(2+3i)(1-2i) = (8-i)

Explanation:

The given complex number is :

Z = (2+3i)(1-2i)

We need to find the product of the complex number

`Z=2(1)+2(-2i)+3i(1)-6i^2\\\\=2-4i+3i-6i^2`

We know that,
`i^2=-1`

`Z=2-i-6(-1)\\\\=2-i+6\\\\=8-i`

Hence, the product of the complex number is (8-i).