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What are the roots of this quartaic equation? -102 + 12r - 9 = 0

What are the roots of this quartaic equation? -102 + 12r - 9 = 0
asked 41.2k views
4 votes
What are the roots of this quartaic equation?
-102 + 12r - 9 = 0

asked
User Reza Ahmadi
by
8.0k points

2 Answers

1 vote

Answer:

0

Explanation:

answered
User Meisam Sabaghi
by
8.8k points
5 votes

Answer:


r = (37)/(4)

I hope this helps!

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User Oim
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