Question

Please help!! Thank u!!
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Answer 1

Explanation:

in Δ ADM and Δ CBM

AD║BC and AC cuts it.

so ∠DAM=∠BCM (alternate angle)

∠AMD=∠CMB ( vertically opposite angles)

AM=CM (given ,M is mid point of AC)

Hence ΔAMD ≡ ΔCMB (ASA=ASA)

AD=CB