Question

F(x) =5x^2-20x+3 how to find minimum

Answer 1

(2,-17) should be the minimum.

Explanation:

The minimum of a quadratic function occurs at
`x=-(b)/(2a)` . If a is positive, the minimum value of the function is
`f(-(b)/(2a))`

`f_(min)x=ax^2+bx+c` occurs at
`x=-(b)/(2a)`

Find the value of
`x=-(b)/(2a)`

x = 2

evaluate f(2).

replace the variable x with 2 in the expression.

`f(2)=5(2)^2-20(2)+3`

simplify the result.

`f(2)=5(4)-20(2)+3`

`f(2)=20-40+3`

`f(2)=-17`

The final answer is -17

Use the x and y values to find where the minimum occurs.

HOPE THIS HELPS!