Question

Beverage A and Beverage B are sold in identical cans. Beverage A is 4% sugar. The portion of Beverage B that is sugar is 0.21. How many times more sugar is in Beverage B than Beverage A? Write your answer as a decimal.

Answer 1

5.25 times

Explanation:

Beverage A and Beverage B are sold in identical cans.

From the above question

Beverage A is 4% sugar.

The portion of Beverage B that is sugar is 0.21.

Converting Portion of sugar in Beverage B to percentage we have :

0.21 × 100

= 21%

How many times more sugar is in Beverage B than Beverage A?

This is calculated as:

% Beverage B/% Beverage A

= 21%/4%

= 5.25

Hence Beverage B has 5.25 times more sugar than Beverage A.