Question

The density of a particular brand of corn syrup is known to be' 1360 g/L. If Ai-Lin determined the density to be 1372 g/L, then what is the percent error of Ai-Lin's experiment

Answer 1

Answer: 0.87%

Explanation:

Percent error =
`\frac{|\text{ Estimated value - actual value}|}{\text{actual value}}*100\\`

Given: Estimated density = 1360 g/L

Actual value = 1372 g/L

Percent error =
`(|1360-1372|)/(1372)*100\\\\`

`(|-12|)/(1372)*100\%\\\\= (12)/(1372)*100\approx0.87\%`

Hence, the percent error of Ai-Lin's experiment = 0.87%