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Upon balancing the equation what is the smallest possible integers that goes in front O₂? HBr + O₂ ➞ H₂O + Br₂ * 4 points 1 2 3 4

Upon balancing the equation what is the smallest possible integers that goes in front O₂? HBr + O₂ ➞ H₂O + Br₂ * 4 points 1 2 3 4
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Upon balancing the equation what is the smallest possible integers that goes in front O₂? HBr + O₂ ➞ H₂O + Br₂ *

4 points
1
2
3
4

asked
User Zajke
by
8.0k points

2 Answers

5 votes
1 because there would be equal oxygens on both sides
answered
User Anouar
by
8.8k points
7 votes

Answer:

1

Step-by-step explanation:

4 HBr + O2 → 2H 20 + 2Br 2

...............

answered
User Mateusz Rogulski
by
8.4k points
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