Question

In circle R with mZQRS = 74 and QR = 17 units find area of sector QRS. Round

to the nearest hundredth.

Answer 1

`A=186.70\ \text{unit}^2`

Step-by-step explanation:

Given that,

`\angle QRS = 74^(\circ)\\\\QR = 17\ \text{units}`

We need to find the area of sector QRS. The formula for the area of a sector is given by :

`A=(\theta)/(360)* \pi r^2`

QR = RS = r = 17 units

So,

`A=(74)/(360)* (22)/(7)* (17)^2\\\\=186.70\ \text{unit}^2`

So, the area of sector QRS is
`186.70\ \text{unit}^2`