Question

What is the approximate energy of a photon having a frequency of 4X10^14 Hz? (h= 6.6X10-34 Js)

Answer 1

2.65 x 10⁻¹⁹ J

Step-by-step explanation:

ΔE = h·f = (6.63 x 10⁻³⁴J·s)(4 x 10¹⁴s⁻¹) = 2.65 x 10⁻¹⁹ J