Question

What is the percent of Cr in
Cr203?
(Cr = 52.00 amu, O = 16.00 amu)
[?]%

Answer 1

68.42%

Explanation:

We need to find the percent of Cr in
`Cr_2O_3`.

Mass of Cr = 52 amu

Mass of O = 16 amu

Firstly, we will find the molar mass of
`Cr_2O_3` as follows :

M = 2(52) + 3(16)

M = 152 amu

Percent of Cr in
`Cr_2O_3` will be :

`Cr=(2* 52)/(152)* 100\\\\=68.42\%`

Hence, the required percentage is 68.42%.