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A system performed 145 kJ of work on the surroundings and absorbed 105 kJ of heat from the surroundings. What is the change in energy of the system?

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Answer:

250 kJ

Step-by-step explanation:

Step 1: Given data

  • Work performed by the system (w): 145 kJ (By convention, when the system performs work on the surroundings, w > 0)
  • Heat absorbed by the system (q): 105 kJ (By convention, when the system absorbs heat from the surroundings, q > 0)

Step 2: Calculate the change in the internal energy of the system

The internal energy of a thermodynamic system is the energy contained within it. We can calculate the change in the internal energy (ΔE°) using the following expression.

ΔE° = q + w

ΔE° = 105 kJ + 145 kJ = 250 kJ

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User Ori Dar
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