Question

Solve (x^3-4x)(2x^2-3x)​

Answer 1

= x^2 ( 2x^3- 3x^2 - 8x + 12)

Explanation:

(x^3-4x) (2x^2-3x)

= x^3(2x^2-3x) -4x(2x^2-3x)

= 2x^5-3x^4-8x^3+12x^2

= x^2 ( 2x^3- 3x^2 - 8x + 12)