Question

Water is being pumped into a 12-foot-tall cylindrical tank at a constant rate. • The depth of the water is increasing linearly. • At 1:30 p.M., the water depth was 2.6 feet. • It is now 3:30 p.M., and the depth of the water is 3.8 feet. What will the depth of the water be at 4:00 p.M?

Answer 1

The depth will be 4.1 ft

Explanation:

Here, we have a linear model to work with

Between 1:30 pm and 3:30 pm, there was a difference of 3.8-2.6 = 1.2 ft on the depth

What we can see there is that in 2 hours, there was a difference of 1.2 ft

So the filling rate per hour will be 1.2ft/2 hours = 0.6 ft/hr

Now, we want to know the depth of the water at 4:00 pm

The difference between 3:30 and 4 pm is 30 minutes = 0.5 h

so by addition;

3.8 ft + 0.5(0.6)

will give the depth of the water at 4 pm

That will be;

3.8 + 0.3 = 4.1 ft

We used 3.8 ft as it is the depth at 3:30 pm

Then we need to add what is topping this after 30 minutes of filling using the constant filling rate and the time