Question

4radical7-2(2radical7+radical3)+radical12

Answer 1

Given:

`4√(7)-2(2√(7)+√(3))+√(12)`

To find:

The value of given expression.

Solution:

We have,

`4√(7)-2(2√(7)+√(3))+√(12)`

It can be written as

`=4√(7)-2(2√(7)+√(3))+√(4* 3)`

`=4√(7)-2(2√(7)+√(3))+2√(3)`

Using distributive property, we get

`=4√(7)-2(2√(7))-2(√(3))+2√(3)`

`=4√(7)-4√(7)-2√(3)+2√(3)`

`=0`

Therefore, the value of given expression is 0.