Question

How many moles of NO2 form when
63.25 g N2O5 decompose?

2N₂O54NO₂ + O₂

Answer 1

1.1713 moles

Step-by-step explanation:

RFM of N2O5=108

Moles of N2O5= mass/RFM= 63.25/108=0.5856 moles

Mole ratio of N2O5:NO2= 2:4

Therefore moles of NO2= 4/2*0.5856= 1.1713 moles