Question

In the worlds coolest freezer sodium gas was cool to temperature of 78.5 below zero and then called 194.65 more what was the new temperature of the sodium gas

Answer 1

`-273.15^(\circ)\text{C}`

Explanation:

`T_i` = Initial temperature of sodium gas =
`-78.5^(\circ)\text{C}`

`\Delta T` = Change in temperature of sodium gas =
`-194.65^(\circ)\text{C}`

`T_f` = Final temperature of sodium gas

Change in temperature of gas is given by

`\Delta T=T_f-T_i\\\Rightarrow T_f=\Delta T+T_i\\\Rightarrow T_f=-194.65+(-78.5)\\\Rightarrow \Delta T=-273.15^(\circ)\text{C}`

The new temperature of sodium gas is
`-273.15^(\circ)\text{C}`.