Question

0.450 moles of oxygen gas is subjected to a pressure of 3.00 atm and 75 oC.

What is it's volume (in Liters)?

Answer 1

Use this formula PV=nRT

Rearrange formula , question want V ,so

V=nRT/P

given

P= 3.00 atm

n=0.450 moles

R is ideal gas constant = 0.08206 L atm mol-¹K-¹

T in Kelvin so , (75 + 273)= 348 Kelvin (K)

Then insert all this information given with that rearranged formula V=nRT/P

• so, V= (0.45)(0.08206)(348) / 3.00
• = 4.284 L