Question

Give the equation of a line that is perpendicular to

f(x)= 3x+1 and goes through the point (0, -6).

Answer 1

Answer: -1/3x - 6

Step-by-step explanation: perpendicular lines have opposite reciprocal slopes

original slope of 3 —-> -1/3

then our point is (0, -6) let’s plug that into y=-1/3x+b

-6 = -1/3(0)+b

b= -6

put it all together: y = -1/3x -6