Question

What is the equation of the line that passes through (-3, 4) and (3, -2)?

y = - x - 1
y = x + 7
y = x - 1
y = - x + 1

Answer 1

Just plugging the points into the equations, both fit y=-x+1

Hope this helps

Answer 2

y = -x +1

Explanation:

p1 (-3,4)

p2 ( 3, -2)

line equation y = mx + b

The slope m equals

`(y2 - 21)/(x2 - x1)`

`( - 2 - 4)/(3 - - 3) = ( - 6)/(6) = - 1`

y = - x + b

from any point

-2 = -3 + b

b = 1

line equation = y = -x +1