Question

What is log7 12+log7m-log7n?

Answer 1

Hello!

`\large\boxed{\log_(7){((12m)/(n)})}`

Use the log properties to simplify:

log (a) + log (b) = log (a · b)

log (a) - log (b) = log (a ÷ b)

Therefore:

`log_(7)12 + log_(7)m - log_(7)n\\\\= log_(7)(12 * m / n}\\\\log_(7){((12m)/(n)})`